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One solution is to label the coins with the letters FAKE MIND CLOT and weigh the coins in the following three combinations:
(先把硬幣標上FAKE MIND CLOT"英文字母"的記號, 然後開如下圖方法秤3次)

MA DO -- LIKE
ME TO -- FIND
FAKE  -- COIN

全句就是: MA DO LIKE ME TO FIND FAKE COIN.

Logic will now allow you to find the fake coin based on the three results. For instance, if the results were left down, balanced, left down, we could work out which coin is fake in the following way:  (假如秤三次的結果分別為: 左低, 平衡, 左低)

A - appears on the left twice and could be fake. 在左邊出現2次, 有機會假
C - appears only once, therefore can't be fake (otherwise the first weighing would be balanced). 只出現一次, 不可能假
K - appears on opposite sides, so it can't make the left side go down both times. 左右兩邊各出現一次, 不可能假
L - appears only once, therefore can't be fake (otherwise the third weighing would be balanced). 只出現一次, 不可能假

Therefore the only possibility is A, which must be heavier. Any other combination of ups and downs will allow you to use the same logic to find the fake coin. (所以A是假的)

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6個6個
一堆左一堆右
如果假硬幣那邊比較重就是比較重
比較輕就比較輕
亂打的(炸
煌龍
阿銀逼機臉

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2# 35082326
那如果假的在6對6的重那邊呢?
29287319 發表於 2011-4-11 07:31

把輕改成重

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2# 35082326
那如果假的在6對6的重那邊呢?
飛空。

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6對6。
哪方比較輕就把那方分成3枚跟3枚。
3對3。
哪方比較輕就分成1枚對1枚,多餘的等等再用。
1對1。
一樣重代表多餘的假的。
不一樣中就拿多餘的一個一個用手測。
感覺跟其餘十一枚都不一樣的就是假的。
ID:冰星
欠咬······

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